Solved: DelUser not working (for me)

stefan.hoerterer1 · ‎07-08-2015

Problem: I Call DelUser, it returns sucess, but the user is still beeing listed/ still there. Am I missing something? Thank you.

Request

<?xml version="1.0" encoding="UTF-8"?>
<serv:message xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:serv="http://www.webex.com/schemas/2002/06/service">

</securityContext>

</header>

<body>

<webExId>webexidtodel</webExId>

</bodyContent>

</body>

</serv:message>

Response

<?xml version="1.0" encoding="UTF-8"?>
<serv:message xmlns:serv="http://www.webex.com/schemas/2002/06/service"
xmlns:com="http://www.webex.com/schemas/2002/06/common"
xmlns:use="http://www.webex.com/schemas/2002/06/service/user">

<serv:header>

<serv:response>

<serv:result>SUCCESS</serv:result>

<serv:gsbStatus>PRIMARY</serv:gsbStatus>

</serv:response>

</serv:header>

<serv:body>

<serv:bodyContent xsi:type="use:delUserResponse"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"/>

</serv:body>

</serv:message>

nmorrow · ‎07-08-2015

Hello,

This is due to a security audit several years ago. DelUser is retained for backward compatibility, but will only deactivate users instead of deleting. Inactive users do not count toward site license restrictions, if any, but they do count against email address and username uniqueness check. You can use SetUser to deactivate accounts and also update the email address and username to something that won't cause conflict in the future, such as appending the current date/time.

View solution in original post

nmorrow · ‎07-08-2015

Hello,

This is due to a security audit several years ago. DelUser is retained for backward compatibility, but will only deactivate users instead of deleting. Inactive users do not count toward site license restrictions, if any, but they do count against email address and username uniqueness check. You can use SetUser to deactivate accounts and also update the email address and username to something that won't cause conflict in the future, such as appending the current date/time.

stefan.hoerterer1 · ‎07-08-2015

Oh, that's awkward, but at least I got it now. Thank you for the quick reply.